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[Ch3] Supplement integral for 3-18 #2

@pingpingy1

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@pingpingy1

What is the content you want to add? What problem is it the solution to?
For a fully rigorous solution, we need to add a proof that
$$\int_0^\infty dx \frac{\ln x}{1 + x^2} = 0,$$
which is indeed true according to WolframAlpha.
This could be done by integrating $\frac{{\left( \ln z \right)}^2}{1 + z^2}$ along the same contour.

Additional context
Perhaps we could generalize this as $$I_n := \int_0^\infty dx \frac{{\left( \ln x \right)}^n}{1 + x^2},$$ for which we may be able to find a recurrence relation for by integrating $$\frac{{\left( \ln z \right)}^{n + 1}}{1 + z^2}.$$

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